(7/y+3)-(9/y-3)=8/y^2-9

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Solution for (7/y+3)-(9/y-3)=8/y^2-9 equation: 



(7/y+3)-(9/y-3)=8/y^2-9

We move all terms to the left:

(7/y+3)-(9/y-3)-(8/y^2-9)=0



Domain of the equation: y+3)!=0

y∈R





Domain of the equation: y-3)!=0

y∈R





Domain of the equation: y^2-9)!=0

y∈R



We get rid of parentheses

7/y-9/y-8/y^2+3+3+9=0

We calculate fractions

We do not support eypression: y^3

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